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Explanation: Direction cosines are the cosines of the angles a line makes with the coordinate axes. Using the given angles, the direction cosines are calculated as cos(60°), cos(45°), and cos(135°), which are ±(1/2), ±(1/√2), and ±(1/√2) respectively. The sign depends on the direction of the line.
Explanation: Direction ratios are proportional to direction cosines. Multiplying the direction cosines (1/2, -1/2, -1/2) by 2 gives the direction ratios (1, -1, -1). This maintains proportionality while using integer values.
Explanation: To check for collinearity, verify if the direction ratios of AB and BC are proportional. AB has direction ratios (-3, -5, -3) and BC has direction ratios (6, 10, 6). These are proportional with a factor of -2, confirming collinearity.
Explanation: The Cartesian equation of a line passing through a point (x₁, y₁, z₁) and parallel to a direction vector (a, b, c) is given by (x-x₁)/a = (y-y₁)/b = (z-z₁)/c. Substituting the values gives (x-2)/1 = (y-3)/2 = (z-4)/3.
Explanation: The shortest distance between skew lines r = a₁ + λb₁ and r = a₂ + μb₂ is |(a₂ - a₁) · (b₁ × b₂)| / |b₁ × b₂|. Here, a₁ = i + 2j + 3k, b₁ = i - j + k, a₂ = 2i - j + k, b₂ = 2i + j - k. Calculating the cross product and dot product yields the distance as 6/√6.
Explanation: The angle θ between two lines with direction ratios (a₁, b₁, c₁) and (a₂, b₂, c₂) is given by cosθ = (a₁a₂ + b₁b₂ + c₁c₂) / √(a₁² + b₁² + c₁²)√(a₂² + b₂² + c₂²). Substituting the values gives cosθ = (1*1 + 1*0 + 0*1) / √(1² + 1² + 0²)√(1² + 0² + 1²) = 1/√3.
Explanation: The vector equation of a line passing through a point a = (x₁, y₁, z₁) and parallel to a vector b = (a, b, c) is r = a + λb. Substituting the given values gives r = (1, 2, 3) + λ(2, 3, 4).
Explanation: The direction cosines are the normalized direction ratios. The magnitude of the direction ratios (2, -2, 1) is √(2² + (-2)² + 1²) = 3. Normalizing gives direction cosines (2/3, -2/3, 1/3).
Explanation: The shortest distance between parallel lines r = a₁ + λb and r = a₂ + μb is |(a₂ - a₁) × b| / |b|. Here, a₁ = i + j + k, a₂ = 2i - j + 3k, b = 2i - j + k. Calculating the cross product and magnitude yields the distance as 1/√6.
Explanation: The Cartesian equation of a line passing through a point (x₁, y₁, z₁) and having direction ratios (a, b, c) is given by (x-x₁)/a = (y-y₁)/b = (z-z₁)/c. Substituting the values gives (x-1)/1 = (y-2)/2 = (z-3)/3.
Explanation: To check collinearity, verify if the direction ratios of AB and BC are proportional. AB has direction ratios (3, 3, 3) and BC has direction ratios (3, 3, 3). Since these are identical, the points are collinear.
Explanation: The angle θ between two lines with direction cosines (l₁, m₁, n₁) and (l₂, m₂, n₂) is given by cosθ = l₁l₂ + m₁m₂ + n₁n₂. Substituting the values gives cosθ = (1/√3)(1/2) + (1/√3)(1/2) + (1/√3)(0) = 1/√2.
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